-6u^2-5u+1=0

Solution for -6u^2-5u+1=0 equation:

-6u^2-5u+1=0

a = -6; b = -5; c = +1;
Δ = b2-4ac
Δ = -52-4·(-6)·1
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-7}{2*-6}=\frac{-2}{-12}
=1/6
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+7}{2*-6}=\frac{12}{-12}
=-1
$